UVa 10302 - Summation of Polynomials

Contents

1. 1. Problem
2. 2. Solution
3. 3. Code

Problem

題目網址
中文網址

Solution

DP 建表。

Code

UVa 10302

#include<cstdio>

int main()
{
    long long ans[50001] = {};
    for (int i = 1; i < 50001; i++)
        ans[i] = ans[i - 1] + (long long)i*i*i;
    int n;
    while (scanf("%d", &n) != EOF)
        printf("%lld\n", ans[n]);

    return 0;
}