UVa 253 - Cube painting

Contents

  1. 1. Problem
  2. 2. Solution
  3. 3. Code

Problem

中文網址

Solution

利用翻轉骰子來替換最上面的,總共 6 面。每次以不同的面當最上面時,再旋轉四次側面,去比對有沒有一樣的。

Code

UVa 253
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#include<cstdio>

char str1[6], str2[6];
inline void clockwise()//順時針旋轉
{
int temp = str2[4];
str2[4] = str2[2];
str2[2] = str2[1];
str2[1] = str2[3];
str2[3] = temp;
}
inline void forward()//向前滾
{
int temp = str2[5];
str2[5] = str2[4];
str2[4] = str2[0];
str2[0] = str2[1];
str2[1] = temp;
}
inline void turnRight()//向右翻
{
int temp = str2[3];
str2[3] = str2[0];
str2[0] = str2[2];
str2[2] = str2[5];
str2[5] = temp;
}
inline bool cmp()
{
for (int i = 0; i < 6; i++)
if (str1[i] != str2[i])
return false;
return true;
}
int main()
{
while ((str1[0] = getchar()) != EOF)
{
int i;
for (i = 1; i < 6; i++)
str1[i] = getchar();
for (i = 0; i < 6; i++)
str2[i] = getchar();
getchar();

bool ok = false;

//以不同的 6 個面當最上面,去做4次旋轉
for (int i = 0; i < 4 && !ok; i++)
{
for (int j = 0; j < 4; j++)
{
if (cmp())
{
ok = true;
break;
}
clockwise();
}
forward();
}

for (int i = 0; i < 4 && !ok; i++)
{
for (int j = 0; j < 4; j++)
{
if (cmp())
{
ok = true;
break;
}
clockwise();
}

turnRight();
}

puts(ok ? "TRUE" : "FALSE");
}

return 0;
}